Math, asked by athang07, 1 year ago

sin80°/cos10°+sin59°sec31°​

Answers

Answered by Anonymous
6

Hii....

 \frac{ \sin(80) }{ \cos(10) }  +  \sin(59)  \sec(31)  \\  \frac{ \cos(90 - 10) }{ \cos(10) }  +  \cos(90 - 31)  \sec(31)  \\   \frac{ \cos(10) }{ \cos(10) }  +  \cos(31)  \frac{1}{ \cos(31) }  \\ 1 + 1 \\ 2

HOPE THIS HELPS YOU...❤❤

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