Math, asked by starabhishekrock123, 10 months ago

Sin85-sin25-cos55=?

Answers

Answered by Anonymous
25

\huge\bold{Answer}

sin85 - sin25 - cos55

2(cos \frac{85 + 25}{2} )(sin \frac{85 - 25}{2} ) - cos55

2cos( \frac{110}{2} )sin( \frac{60}{2} ) - cos55

2.cos55.sin30 - cos55

By taking " \bf\pink{cos55} " as common.

cos55(2sin30 - 1)

cos55(2 \times ( \frac{1}{2} ) - 1)

cos55 \times (0) = 0

\bf\red{Identity\:used:-}

\bf\boxed{sinC-SinD=2.(cos\frac{C+D}{2}).(sin\frac{C-D}{2})}

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