Question

Sin8A= 8sinA.cosA.cos2A.cos4A

Answer 1

Answer:

Sin8A= 8sinA.cosA.cos2A.cos4A

Answer 2

SOLUTION

TO PROVE

Sin 8A = 8sinA.cosA.cos2A.cos4A

FORMULA TO BE IMPLEMENTED

We are aware of the Trigonometric formula that

Sin 2A = 2 sin A cos A

EVALUATION

Sin 8A

= sin ( 2.4A)

= 2 sin 4A cos 4A

= 2 × 2 sin 2A cos 2A cos 4A

= 4 sin 2A cos 2A cos 4A

= 4 × 2 sin A cos A cos 2A cos 4A

= 8 sin A cos A cos 2A cos 4A

Hence proved

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If cosθ+secθ=√2,find the value of cos²θ+sec²θ

https://brainly.in/question/25478419

2. Value of 3 + cot 80 cot 20/cot80+cot20 is equal to

https://brainly.in/question/17024513

3. In a triangle, prove that (b+c-a)(cotB/2+cotC/2)=2a×cotA/2

https://brainly.in/question/19793971