Math, asked by sunny94, 1 year ago

sin8A/sinA = 8cosA cos2A cos4A

Answers

Answered by ARoy

sin8A/sinA
=sin(2.4A)/sinA
=2sin4Acos4A/sinA
=2sin(2.2A)cos4A/sinA
=2(2sin2Acos2A)cos4A/sinA
=4sin2Acos2Acos4A/sinA
=4(2sinAcosA)cos2Acos4A/sinA
=8sinAcosAcos2Acos4A/sinA
=8cosAcos2Acos4A(Proved)

Answered by Uppara

Answer:

Step-by-step explanation:

Sin8A=2sinA(4A)cos(4A)

2{(2sin(2A)cos(2A)} cos(4A)

2{2(sinAcosA)}(cos2A cos4A)

8sinA cosA cos2A cos4A

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