Math, asked by gautam113, 1 year ago

sin90/cos45 + 1/cosec30

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Answered by shubhamtiwari31
5
1/(1/root 2) + 1/2
root 2+ 1/2
(2root2 + 1)/2


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Answered by rohanharolikar
1
sin(90)/cos(45) + 1/cosec(30)
= 1/(1/√2) + 1/2
= √2 + 1/2
= (2√2 + 1)/√2
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