Question

sinA=1/2,c osB=√3/2 find tan{A+B}

Answer 1

tan (a + b) = tan a + tan b /1 - tana×tanb
=sin a/ cos a + sinb / cos b / 1 - sinasinb/ cos a cos b
=sin (a+b)/ cos (a+b)
sin (a+b) = sinacosb + cosasinb
cos (a+b)=cosacosb - sinasinb
cos a and sin b can be calculated by using identities