Math, asked by shaikafsheen94, 4 months ago

SinA = 1/2 cosB= 1/2 prove that sin (A+B)=1​

Answers

Answered by Smileygirl123
2

Step-by-step explanation:

Given that -

sinA = 1/2 & cosB= 1/2

so, cosA = √(1-sin²A)

cosA = √3/2

similarly, sinB = √(1-cos²B)

sinB = √3/2

we know that

sin (A+B) = sinAcosB + cosAsinB

sin (A+B) = 1/2 × 1/2 + √3/2 × √3/2

sin (A+B) = 1/4 + 3/4

sin (A+B) = 1

It's proved.✌️

Hopes it will help you.

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