SinA = 1/2 cosB= 1/2 prove that sin (A+B)=1
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Step-by-step explanation:
Given that -
sinA = 1/2 & cosB= 1/2
so, cosA = √(1-sin²A)
cosA = √3/2
similarly, sinB = √(1-cos²B)
sinB = √3/2
we know that
sin (A+B) = sinAcosB + cosAsinB
sin (A+B) = 1/2 × 1/2 + √3/2 × √3/2
sin (A+B) = 1/4 + 3/4
sin (A+B) = 1
It's proved.✌️
Hopes it will help you.
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