Question

SinA/1+cosA + 1+cosA/sina = 2 cosec A

Answer 1

howdy !!

your answer is in the above pic ☝☝☝



hope it help you
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Answer 2

Hi...☺

Here is your answer...✌

LHS

$= \frac{sinA}{1 + cosA} + \frac{1 + cosA}{sinA} \\ \\ = \frac{sin {}^{2} A + {(1 + cosA)}^{2} }{(1 + cosA)(sinA)} \\ \\ = \frac{sin {}^{2} A + {1 + cos {}^{2} A + 2cos A}}{(1 + cosA)(sinA)} \\ \\ = \frac{1+ 1+ 2cos A}{(1 + cosA)(sinA)} \\ \\ = \frac{2+ 2cos A}{(1 + cosA)(sinA)} \\ \\ = \frac{2( 1+cos A)}{(1 + cosA)(sinA)} \\ \\ = \frac{2}{sinA} \\ \\ = 2cosecA$

= RHS [ Proved ]