Question

sinA÷1+cosA + 1+cosA÷sinA=2 cosecA

Answer 1

I hope you are satisfied

Answer 2

To prove, sinA/1+cosA + 1+cosA/sinA=2cosecA
L.H.S. = sinA/1+cosA + 1+cosA/sinA 
= [sin^2A + (1 + cosA)^2]/sinA(1 + cosA) 
= (sin^2A + 1 + cos^2A + 2cosA)/sinA(1 + cosA) 
= (1 + 1 + 2cosA)/sinA(1 + cosA) [since,sin^2A + cos^2A = 1]
= (2 + 2cosA)/sinA(1 + cosA) 
= 2(1 + cosA)/sinA(1 + cosA) = 2/sinA 
= 2 cosecA [since 1/sinA = cosecA]
= R.H.S.
Hence, Proved

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