Question

sinA/1+cosA + 1+cosA/sinA​

Answer 1

Question

sinA/1+cosA + 1+cosA/sinA

Solution

SinA/(1 + CosA) + (1 + CosA)/SinA

= [(SinA)^2 + (1+CosA)^2]/[SinA(1 + CosA)]

= [(SinA)^2 + (CosA)^2 + 1 + 2CosA]/[SinA(1 + CosA)]

= [2(1 + CosA)]/[SinA(1 + CosA)]

( since, (SinA)^2 + (CosA)^2 = 1 )

= 2/SinA = 2CosecA

Hence LHS=RHS.

$bts ❤ exo$

Answer 2

Answer:

see the attachment

Step-by-step explanation:

hope it helps you