Question

sinA/1+cosA+1+cosA/sinA = 2cosec A​

Answer 1

Answer:

SinA/1+cosA+1+ cosA/SinA

SinA/1+ 1/SinA

CosecA+ CosecA

=2cosecA

Step-by-step explanation:

Answer 2

L.H.S sinA/1+cosA + 1+cosA/sinA

= sin^2 + (1+cosA)^2/sinA(1+cosA)

= sin^2 + 1 + cos^2A + 2cosA/sinA(1+cosA)

= sin^2 + cos^2A + 1+ 2cosA /sinA(1+cosA)

= 1 + 1 + 2cosA/sinA(1+cosA)

= 2 + 2cosA/sinA(1+cosA)

= 2(1+cosA)/sinA(1+cosA)

= 2/sinA = 2cosecA = R.H.S

Proved