sinA/1+cosA+1+cosA/sinA=2cosecA
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Answer:
bro it's solved by you and your question
Answered by
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Step-by-step explanation:
(sinA/1+cosA)+(1+cosA/sinA) = 2cscA?
Work on LHS
sinA/(1+cosA)+(1+cosA)/sinA
=[sin^2A + (1 + cosA)^2]/[sinA(1 + cosA)]
=[sin^2A + 1 + 2cosA + cos^2A]/[sinA(1 + cosA)]
=[(sin^2A + cos^2A) + 1 + 2cosA]/[sinA(1 + cosA)]
=[1 + 1 + 2cosA]/[sinA(1 + cosA)]
=[2 + 2cosA]/[sinA(1 + cosA)]
=[2(1 + cosA)]/[sinA(1 + cosA)]
=2/sinA
=2(1/sinA)
=2cosec A
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