Question

sinA/1+cosA+1+cosA/sinA=2cosecA
​

Answer 1

Step-by-step explanation:

L.H.S. =

sinA

1+cosA

+

1+cosA

sinA

=

sinA(1+cosA)

(1+cosA)(1+cosA)+sinAsinA

=

(1+cosA)sinA

(1+cosA)

2

+sin

2

A

=

(1+cosA)sinA

1+cos

2

A+2cosA+sin

2

A

=

(1+cosA)sinA

1+2cosA+1

=

(1+cosA)sinA

2+2cosA

=

(1+cosA)sinA

2(1+cosA)

=2

sinA

1

=2cosecA

=R.H.S

Hence proved.

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