SinA/1+cosA=cosecA-cotA
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TO PROVE :
PROOF =>
LHS =
Multiply , (1 - cos A) in numerator and denominator , we get ,
=> sin A ( 1 - cos A ) / ( 1 + cos A) ( 1 - cos A )
=> sin A ( 1 - cos A ) / sin² A
As , sin² A + cos² A = 1
=> 1-cos² A = sin² A
=> ( 1 + cos A) (1 - cos A) = sin² A
and ,
=> ( 1 - cos A ) / sin A
=> 1 / sin A - cos A / sin A
=> cosec A - cot A = RHS .....
PROVED!
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