Math, asked by nihar568, 1 year ago

sinA/ [1+cosA]= cosecA - cotA

Answers

Answered by shivakumarah
3

sinA/(1+cosA)

=sinA/(1+cosA)×(1-cosA)/(1-cosA)

=sinA-sinA cosA /1-cos2(A)

=sinA/1-cos2(A)-sinA cosA/1-cos2(A)

=sinA/sin2(A)-sinA cosA/sin2(A)

=cosecA-cotA

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