Math, asked by green333, 1 year ago

sinA/1+cosA +sinA/1-cosA =​

Answers

Answered by 217him217
1

(sinA/1+cosA) + (sinA/1-cosA)

= (sinA - sinAcosA + sinA + sinAcosA) /1-cos²A

=(2sinA) /sin²A

=2/sinA

=2cosecA

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