Math, asked by nick1901, 1 year ago

sinA/1-cotA+cosA/1-tanA

Answers

Answered by kaushikravikant
5
SinA/1- cotA + cosA/1-tanA
Open tanA as sinA/cosA and cotA as cosA/sinA
 Sin²A/ sinA-cosA + cos²A/cosA-sinA
 Sin²A/sinA-cosA - cos²A/ sinA-cosA
On taking lcm
 Sin²A -cos²A /sinA-cosA
Open identity a²-b² = (a-b..)(a+b)
 (SinA+ cosA)(SinA - CosA)/(SinA -CoSA)
(SinA+ CosA)

kaushikravikant: mark as best please
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