Math, asked by rockstar2063, 10 months ago

(sinA/1-cotA)+(cosA/1-tanA)=cosA+sinA

Answers

Answered by sandy1816

0

Step-by-step explanation:

(sinA/1-cotA)+(cosA/1-tanA)

=(sin²A/sinA-cosA)+(cos²A/cosA-sinA)

=(sin²A/sinA-cosA)-(cos²A/sinA-cosA)

=(sin²A-cos²A)/(sinA-cosA)

=(sinA+cosA)(sinA-cosA)/(sinA-cosA)

=sinA+cosA

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