Question

sinA/1-cotA+cosA/tanA=sinA+cosA​

Answer 1

Answer:

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Answer 2

$\frac{sinA}{1 - cotA} + \frac{cosA}{1 - tanA} \\ \\ = \frac{ {sin}^{2}A }{sinA - cosA} + \frac{ {cos}^{2}A }{cosA - sinA} \\ \\ = \frac{ {sin}^{2}A }{sinA - cosA} - \frac{ {cos}^{2} A}{sinA - cosA} \\ \\ = \frac{ {sin}^{2}A - {cos}^{2} A}{sinA - cosA} \\ \\ = sinA + cosA$