SinA(1+tanA) + cosA(1+cotA)=secA+cosecA
Answers
Answered by
0
Step-by-step explanation:
LHS,
sinA(1+tanA)+cosA(1+cotA)
=sinA+sin^2A/cosA+cosA+cos^2A/sinA
=(sinA+cos^2A/sinA)+(cosA+sin^2A/cosA)
=(sin^2A+cos^2A)/sinA+(cos^2A+sin^2A)/cosA
=1/sinA+1/cosA
=cosecA+secA=RHS
Answered by
0
Answer:
= secA+cosecA
Step-by-step explanation:
= sinA(1+tanA)+cosA (1+cos+A)
= sinA+sinA tanA+cosA cot
=sinA+sinA×sinA/cosA+cosA+cosA
= sinA+sinA2/cosA+cosA+cosA2/sinA
= sinA2+cosA2/sinA+cosA2+sinA2/cosA
=1/sinA+1/cosA
=secA+cosecA
Similar questions