Question

SinA(1+tanA)+cosA(1+cotA)=secA+cossecA

Answer 1

Step-by-step explanation:

sinA(1+tanA)+cosA(1+cotA)

=sinA(cosA+sinA/cosA)+cosA(sinA+cosA/sinA)

=sin²A(cosA+sinA)+cos²A(cosA+sinA)/sinAcosA

=(cosA+sinA)(sin²A+cos²A)/sinAcosA

=cosA+sinA/sinAcosA

=1/sinA+1/cosA

=cosecA+secA