Question

(sinA/2+sinA)/(1+cosA/2+cosA)=tanA/2

Answer 1

Step-by-step explanation:

in nominator , break sinA to 2sin(A/2)cos(A/2)

and take sin(A/2) as common.

in de-nominator , take (1+cosA) and turn it to 2cos(A/2)^2........and take cos(A/2) as common