Math, asked by Anu02322, 10 months ago

sinA-2sin3A/2cos3a-cosa

Answers

Answered by abhiprince633

5

Step-by-step explanation:

sinA (1-2sin2A)/cosA (2cos2A-1)
sinA (1-2 (1-cos2A)/cosA (2cos2A-1)
sinA (-1+2cos2A)/cosA (2cos2A-1)
sinA/CosA
tanA........

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