Question

SinA=^3/2 then find sinACosA

Answer 1

Answer:

sinA =

$\frac{ \sqrt{3} }{2}$

sin 60° =

$\frac{ \sqrt{3} }{2}$

therefore A=60°

now,

cosA=cos60°=1/2

therefore

SinACosA

=sin60°×cos60°

=

$\frac{ \sqrt{3} }{2} \times \frac{1}{2} = \frac{ \sqrt{3} }{4}$