sinA = 3/4 calculate cot A and sec A
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Answered by
2
Answer:
sinA = 3/4
H²=P²+B²=> (4k)²=(3k)²+B²
B²= 16k²-9k² = 7k²
B=√7k
cotA=B/P= √7k/3k= √7/3
secA= H/B= 4k/√7k = 4/√7
Answered by
1
Answer:
- cot A=
/3
- sec A=4/
Step-by-step explanation:
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