Math, asked by pekka9, 6 months ago

sinA = 3/4 calculate cot A and sec A

Answers

Answered by anurag2147

2

Answer:

sinA = 3/4

H²=P²+B²=> (4k)²=(3k)²+B²

B²= 16k²-9k² = 7k²

B=√7k

cotA=B/P= √7k/3k= √7/3

secA= H/B= 4k/√7k = 4/√7

Answered by Anonymous

1

Answer:

cot A= $\sqrt7\\$ /3

sec A=4/ $\sqrt7$

Step-by-step explanation:

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