Question

sinA = 3/4, find the values of cosA and cotA​

Answer 1

Answer:

cos² A = 1 - sin²A

cos² A = 1 - (3/4)²

cos² A = 1 - (9/16)

cos² A = (16 - 9)/ 16

cos² A = 7/16

cos A = plus/minus $\sqrt{7} \div 4$

cot A = sin A / cos A

cot A = (3/4) ÷ plus/minus root 7/4

cot A = 3/root 7

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