Question

sinA=3/4 then find cosA and tanA​

Answer 1

Step-by-step explanation:

refer attachment

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Answer 2

sin A= 3/4

let perpendicular(p) = 3

and hypotenuse(h) be 4

by using pythogorus theorum base (b) will be

p×p+b×b= h×h

b×b=h×h--p×p

b×b =4×4--3×3

b×b =16--9

b×b =7

b= root 7 then

cosA =root7/4

tanA=3/root7