Question

sinA=3/4calculate cosA and tanA​.

Answer 1

Answer:

$cosA = \frac{\sqrt{7}}{4}$

$tanA =\frac{3}{\sqrt{7}}$

Step-by-step explanation:

$Given \: sinA=\frac{3}{4}$

$cosA \\=\sqrt{1-sin^{2}A}\\=\sqrt{1-\left(\frac{3}{4}\right)^{2}}\\=\sqrt{1-\frac{9}{16}}\\=\sqrt{\frac{16-9}{16}}\\=\sqrt{\frac{7}{16}}\\=\frac{\sqrt{7}}{4}$

$tan A = \frac{sinA}{cosA}\\=\frac{\frac{3}{4}}{\frac{\sqrt{7}}{4}}\\=\frac{3}{\sqrt{7}}$

Therefore,

$cosA = \frac{\sqrt{7}}{4}$

$tanA =\frac{3}{\sqrt{7}}$

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Answer 2

Answer:

the answer is 19/4 root 7...