Question

sinA=3/5, cos B=1/3, find sin(A+B) and sin(A-B)​

Answer 1

Answer:

Hope This Is Helpful !!

Step-by-step explanation:

SinA = 3/5. and cosB = 5/13

CosA = 4/5 and sinB = 12/13

Sin(a + b) = sinA. cosB + cosa. sinB

Sin(a + b) = 3/5 * 5/13 + 4/5 * 12/13

Sin(a + b) = 15/65 + 48/65

Sin(a + b) = 63 / 65

Sin(a - b) =  sinA cosB − cosA sinB

Sin(a - b) = 3/5 * 5/13 - 4/5 * 12/13

Sin(a - b) = 3/13 - 48/65

Sin(a - b) = 15/65 + 48/65

Sin(a - b) = -33/65