sinA=3/5, cos B=1/3, find sin(A+B) and sin(A-B)
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Step-by-step explanation:
SinA = 3/5. and cosB = 5/13
CosA = 4/5 and sinB = 12/13
Sin(a + b) = sinA. cosB + cosa. sinB
Sin(a + b) = 3/5 * 5/13 + 4/5 * 12/13
Sin(a + b) = 15/65 + 48/65
Sin(a + b) = 63 / 65
Sin(a - b) = sinA cosB − cosA sinB
Sin(a - b) = 3/5 * 5/13 - 4/5 * 12/13
Sin(a - b) = 3/13 - 48/65
Sin(a - b) = 15/65 + 48/65
Sin(a - b) = -33/65
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