sinA=3/5,tanB=1/2,then find 8tanA-root5×secB
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in this question Pythagoras theorem is used
sinA=3/5
tanB=1/2then,
tanA= 3/4
secB=√5/2
according to question,
8tanA-√5*secB
8*3/4-√5*√5/2
6-√15/2
6/1-√15/2
12-√15/2 is the answer
sinA=3/5
tanB=1/2then,
tanA= 3/4
secB=√5/2
according to question,
8tanA-√5*secB
8*3/4-√5*√5/2
6-√15/2
6/1-√15/2
12-√15/2 is the answer
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