Math, asked by GodVasuDev, 1 year ago

(sinA)^3-(cosA)^3 = ?

Answers

Answered by shrishti9653

1

sinA 3 -cosA 3

=

a^3 - b^3 = (a-b)(a^2 -ab+b^2)

(sinA - cosA) (sin^2A - sinA .cosA + cos^2A).

hope its correct

GodVasuDev: yup you are right

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