Math, asked by rastoginishant99, 16 days ago

sinA ^3-cosA^3/sinA -cosA

Answers

Answered by njan7312

0

Step-by-step explanation:

[(sinA)^3-(cosA)^3]/(sinA-cosA)

=[(sinA-cosA)((sinA)^2+sinAcosA+(cosA)^2)]/(sinA-cosA)

[a^3-b^3=(a-b)(a^2+ab+b^2)]

=((sinA)^2+(cosA)^2+sinAcosA)

=(1+sinAcosA). [(sinA)^2+(cosA)^2=1]

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