Question

sinA=√3 , FIND cosecA, cosA, tanA. ​

Answer 1

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sinA = √3

→ sinA = √3/1

Height= √3

Hypotenuse= 1

We know that→

$\sin(A) = \frac{height}{hypotenuse}$

$\csc(A) = \frac{hypotenuse}{height}$

So,

$\csc( A) = \frac{hypotenuse}{height}$

Then ,

$\csc(A) = \frac{1}{ \sqrt{3} }$

• We know that sin²A + cos²A = 1

${sin}^{2} A + {cos}^{2} A = 1 \\ = > {( \sqrt{3}) }^{2} + {cos}^{2} A = 1 \\ = > 3 + {cos}^{2} A = 1 \\ = > {cos}^{2} A = - 2 \\ = > cosA = \sqrt{ - 2}$

★

$\tan(A) = \frac{height}{base}$

Then,

$tanA = \frac{ \sqrt{3} }{ \sqrt{ - 2} }$

★ Answer:-

$\csc(A)= \frac{1}{ \sqrt{3} }$

$\cos(A) = \sqrt{ - 2}$

$\tan(A) = \frac{ \sqrt{3} }{ \sqrt{ - 2} }$

Answer 2

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