Question

SinA=4/5and SinB=5/13 find cosec (A-b)

Answer 1

Step-by-step explanation:

Given ,

Sin A = 4/5

We know that , Sin²A + Cos²A = 1

Therefore , Cos²A = 1- Sin²A

= 1- (4/5)²

= (25-16)/25

= 9/25

Cos A = 3/5

Similarly Cos B = 12/13

We have to find Cosec(A-B)

Sin ( A- B )= SinAcosB - Cos A sin B

= (4/5 )(12/13) - (3/5)(5/13)

= 48-25/13

= 23/13

Therefore Cosec ( A-B )= 13/23

!Hope it helps!!

Answer 2

Answer:

65/16 is right answer how you find your answer