SinA= 4/6 SinB=8/9
sin(A+B)=?
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Answer:
there is a formula of doing this sum
sin(a+b)=sina.cosb+cosa.sinb
sin a=4/6. cosb=8/9
sin²a +cos²a=1
16/36 +cos²a=1
cos²a=1-16/36
=20/36
cosa=√20/√36
=2√5/6
sin²b+cos²b=1
64/81 +cos²b=1
cos²b=1-64/81
=17/81
cosb=√17/9
now,
sin(a+b)=4/6*8/9+2√5/6*√17/9
=32/54+2√95/4
=34√95/54. is the answer
HOPE THIS HELP
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