Question

sinA=5/13 find cosA​

Answer 1

Step-by-step explanation:

sinA=5/13

cosA=√1-sin^2A=√{1-(5/13)^2}=

=>cosA=√(1-(25/169))=√(144/169)

=>cosA=12/13

Answer 2

Step-by-step explanation:

we know that,

sin A = Perpendicular/Hypotenuse

5/13 = Perpendicular/ Hypotenuse

Let the ratio be x

Perpendicular = 5x

Hypotenuse. = 13x

By Pythagoras Theorem

H square = Perpendicular square + Base square

Base square = (13x) square - (5x) square

= (169 - 25) x square

= 12 square

Base. = 12

cos A = 12/13