Question

sinA - √6cosA= √7cosA

Answer 1

Bonjour!

$= > sin \: a \: - \sqrt{6} cos \: a = \sqrt{7} cos \: a \\ \\ = > sin \: a = \sqrt{7} cos \: a + \sqrt{6} cos \: a \\ \\ = > sin \: a = cos \: a( \sqrt{7} + \sqrt{6} ) \\ \\ = > \frac{sin \: a}{cos \: a} = ( \sqrt{7} + \sqrt{6} ) \\ \\ = > tan \: a \: = ( \sqrt{7} + \sqrt{6} )$

Hope this helps...:)

Answer 2

Hi there!

Here's your answer :-

sinA - √6cosA = √7cosA

=> sinA = √7cosA + √6cosA

=> sinA = cosA ( √7 + √6 )

=> sinA / cosA = √7 + √6

=> tanA = √7 + √6

Hence,
The required answer is :- tanA = √7 + √6

Hope it helps!