Question

sinA=a/b then cosA=?​

Answer 1

$\huge\mathfrak\red{AnsweR}$

$\sf SinA = \dfrac{a}{b} = \dfrac{P}{H}$

$\sf B = \sqrt{H^2 - P^2}$

$\sf CosA = \dfrac{\sqrt{H^2 - P^2}}{H}$

Answer 2

$\huge\underline\bold\red{Answer:-}$

$\large\underline\bold\green{Given:-}$

$\dashrightarrow$SinA=a/b

on squring both side

Sin^2 A = (a/b)^2

cos^2A ,= 1 - (a/b)^2

cosA = $\sqrt{ \frac{ {H}^{2} - \: {P}^{2} }{H} }$