Question

SinA+B=cosA-B=√3/2 then what are AAndB

Answer 1

Step-by-step explanation:

Sin(A+B)=cos(A-B)=√3/2

∴, sin(A+B)=√3/2

or, sin(A+B)=sin60°

or, A+B=60° --------------(1)

cos(A-B)=√3/2

or, cos(A-B)=cos30°

or, A-B=30° ---------------(2)

Adding (1) and (2) we get,

2A=90°

or, A=45°

Putting in (1) we get, 

45°+B=60°

or, B=15°

∴, A=45°, B=15°