Question

sinA =con A,
2 Tan^2A+sin^2A-1​

Answer 1

Answer:

sinA =con A,

2 Tan^2A+sin^2A-1

Answer 2

Answer:

$1\frac{1}{2}$

Step-by-step explanation:

Since sin A = cos A,

A = 45°

$2 \tan^{2} (a) + \sin^{2} (a) - 1 \\ = 2 \tan^{2} (45) + \sin^{2} (45) - 1 \\ = 2 \times {1}^{2} + { (\frac{1}{ \sqrt{2} }) }^{2} - 1 \\ = 2 + \frac{1}{2} - 1 = \frac{3}{2} = 1\frac{1}{2}$

Hope this helps. Please mark me as brainliest. Thank you.