Question

sinA×cos(90-A)cosA/sin(90-A) + cosA×sin(90-A)sinA/cos(90-A)​

Answer 1

Answer:

$sin^{2} A + cos^{2} A$

Step-by-step explanation:

sin A * $\frac{cos (90-A) cos A}{sin (90-A)}$ +  cos A * $\frac{sin (90-A) sin A}{cos (90-A)}$

apply the formula

sin (90-∅) = cos∅

cos (90-∅) = sin∅

$sin A * \frac{sin A * cos A}{cos A} + cos A * \frac{cos A}{sin A} * sin A\\\\Sin A * Sin A +Cos A * Cos A\\\\Sin^{2} A + Cos^{2} A$