Question

(sinA+ cos A)(tanA+cotA)= secA+ cosecA​

Answer 1

Answer:

Step-by-step explanation:

QUESTION IS FROM TRIGNOMETRY

LEVEL: V EASY

ANSWER-LOOK IMAGE

Answer 2

Step-by-step explanation:

$(sinA+ cos A)(tanA+cotA)= secA+ cosecA$

$L.H.S.$

$(sinA+ cos A)(tanA+cotA)$

$(sinA +cosA)(\frac{sinA}{cosA} +\frac{cosA}{sinA} )$

$(sinA+ cos A)(\frac{sin^{2}A +cos^{2} A}{sinA.cosA} )$

$(sinA+ cos A)(\frac{1}{sinA.cosA} )$

$\frac{sinA+cosA}{sinA.cosA}$

$\frac{sinA}{sinA.cosA} + \frac{cosA}{sinA.cosA}$

$\frac{1}{cosA} +\frac{1}{sinA}$

$secA + cosecA$

Hence proved.

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