SinA - cosA= 1/2 to find 1/(sinA + CosA)
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If sinA-cosA=1/2 .then find 1/sinA+cosA
1/(sinA + cosA) = 2/√7
Step-by-step explanation:
Given that sin(A) - cos(A) = 1/2
Square both sides, you get
(sin(A) - cos(A))^2 = 1/4
sin^2(A) + cos^(A) - 2sin(A)cos(A) = 1/4
Sin^2(A) + cos^2(A) = 1.
Substituting in above equation
2Sin(A)Cos(A) = 1 - 1/4 = 3/4
Now Take the equation
(Sin(A) + Cos(A))^2 = sin^2(A) + cos^(A) + 2sin(A)cos(A)
= 1 + 2Sin(A)Cos(A) = 1 + 3/4 = 7/4
Apply square root both sides, you get
Sin(A) + Cos(A) = √7/2
Hence 1/(Sin(A) + Cos(A)) = 2/√7
Hope it helps
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