sinA-cosA+1/cosA+sinA-1=1+sinA/cosA
Answers
Answered by
2
Step-by-step explanation:
sinA-cosA+1/cosA+sinA-1
devide cosA in both numerator & denominator
=tanA-1+secA/1+tanA-secA
=(tanA+secA)-(sec²A-tan²A)/1+tanA-secA
=(secA+tanA)(1-secA+tanA)/1+tanA-secA
=secA+tanA
=1/cosA+sinA/cosA
=1+sinA/cosA
Similar questions