sinA+cosA=1, find Angle =A
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Answered by
1
sinA + cosA = 1
if A = 0 degree
then
sin 0 + cos 0 = 0+1 =1 0 is possible
if A =90 degree
then sin90 + cos 90 = 1 + 0 = 1
So for angle A = 0 or 90 degree
if A = 0 degree
then
sin 0 + cos 0 = 0+1 =1 0 is possible
if A =90 degree
then sin90 + cos 90 = 1 + 0 = 1
So for angle A = 0 or 90 degree
abhimanyukumarp4tkxz:
THANKS
Answered by
1
HeY!!
SinA + cosA = 1
Squaring on both side
(SinA + cosA )² = 1²
Sin²A + cos²A + 2sinA×cosA = 1
1 + 2sinA×cosA = 1²
2sinA×cosA = 1 - 1
Sin2A = 0 [ •°• 2sinA×cosA = sin2A ]
sin2A = 0
Sin2A = sin0°
2A = 0
A = 0/2 = 0°
For verification
From LHS
sin0° + cos0°
0 + 1 = 1 = RHS prooved
_____________
Hope it helps you !!
@Rajukumar111
SinA + cosA = 1
Squaring on both side
(SinA + cosA )² = 1²
Sin²A + cos²A + 2sinA×cosA = 1
1 + 2sinA×cosA = 1²
2sinA×cosA = 1 - 1
Sin2A = 0 [ •°• 2sinA×cosA = sin2A ]
sin2A = 0
Sin2A = sin0°
2A = 0
A = 0/2 = 0°
For verification
From LHS
sin0° + cos0°
0 + 1 = 1 = RHS prooved
_____________
Hope it helps you !!
@Rajukumar111
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