Math, asked by rdivyub, 10 months ago

(Sina-cosa+1)/(Sina+Cosa-1)=1/(seca-tana)

Answers

Answered by suryaprakash7

sina - Cosa +1 = 0 seca - tana

Answered by shaivyvi75

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved

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