Math, asked by akashsonkar700nova, 10 months ago

sinA-cosA+1/sinA+cosA+1=1/secA-tanA​

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Answered by sandy1816
4

Answer:

your answer attached in the photo

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Answered by rutujagajhans
1

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved

thank u!!!

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