Question

sinA + COSA+1/sinA +cosA -1=
1/secA-tanA

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$\sin a + \cos a + \frac{1}{ \sin \: a } + \cos \: a - 1 = \frac{1}{ \sec a } - \tan \: a$

$\frac{1}{ \sec a } - \tan a$

$= \cos a - \tan a$

$= \cos a - \frac{ \sin a }{ \cos a}$

$= \frac{ { \cos }^{2}a - \sin a }{ \cos a }$