Question

(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)

Answer 1

Answer:

[sina+cosa]^2-1-{1-sina+cosa+sina-sin^2a+sinacosa-cosa-sinacosa+cos^2a}=2[1+1/sina]

sin^2a+cos^2a+2sinacosa-1-1-cos^2a+sin^2a-2cosasina

sin^2a-cos^2a-1

sin^2a-cos^2a-sin^2a-cos^2a

-2cos^2a is required answer

Step-by-step explanation:

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