sinA-cosA+1/sinA+cosA-1=1+sinA/cosA
Answers
Answered by
1
Step-by-step explanation:
sinA-cosA+1/sinA+cosA-1
devide cosA in both numerator & denominator
tanA-1+secA/tanA+1-secA
=(tanA+secA-1)(tanA+secA)/ {(tanA-secA)+1}(tanA+secA)
=(tanA+secA-1)(tanA+secA)/ tan²A-sec²A+tanA+secA
=(tanA+secA-1)(tanA+secA)/(-1+tanA+secA)
=tanA+secA
=sinA/cosA+1/cosA
=sinA+1/cosA
Answered by
1
Step-by-step explanation:
formula
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a^2-b^2=(a+b)(a-b)
Attachments:
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